Legends World

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We're looking for computer engineers who like to solve difficult problems.Call us on this number now:

x = 24, y = 30

Phone:= 01.(y^2-x).(y^2-10^2)x10

whos gone get the job first heeee

01.876.192000

hfric won't be getting the job then ;\

I_AM wrote:hfric won't be getting the job then ;\

why not? Same result over here....

01.876.8000 ?

Think the second x is a multiplication sign ?

I got the same as Scaryfun, although I would say that I read the .'s as string concatenation, so: 018768000
01.((30^2)-24).(((30^2)-(10^2))*10)

01.876.192000 or 01876192000 isn't a valid phone number.

http://www.google.com/search?&q=01.(y%5E2-x).(y%5E2-10%5E2)x10
The first hits I looked at both agreed with my answer, but the first result for that particular search has as many different answers as people trying to solve it -_-

hmmm what about this solution?

Phone:= 01.(y^2-x).(y^2-10^2)x10
= 01.(30^2-24).(30^2-10^2)2410
= 01.(876).(800)2410
= 018768002410


heee....í´ll try.....riiiiiiiiinnnnnng....riiiiiiinnng......voice speaking:
"We are sorry but we cant connect you through"
damn